(1/v-4)-(4/v+2)=-3/v^2-2v-8

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Solution for (1/v-4)-(4/v+2)=-3/v^2-2v-8 equation: 



(1/v-4)-(4/v+2)=-3/v^2-2v-8

We move all terms to the left:

(1/v-4)-(4/v+2)-(-3/v^2-2v-8)=0



Domain of the equation: v-4)!=0

v∈R





Domain of the equation: v+2)!=0

v∈R





Domain of the equation: v^2-2v-8)!=0

v∈R



We get rid of parentheses

1/v-4/v+3/v^2+2v-4-2+8=0

We calculate fractions

We do not support evpression: v^3

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